what is the bmi of height: 132cm weight:30?
1. what is the bmi of height: 132cm weight:30?
Answer:
17.21
Explanation:
Classification - Underweight
2. if there is a girl of heaight 132cm in the class, there must be a girl of height 128cm. TRUE or FALSE
ANSWER:
(FALSE PO ANG SAGOT)
HOPE IT HELPS. PA BRAINLEIST PO
ANSWER
FALSE
EXPLANATION
BRAINLIEST MEHEART MEFOLLOW MEVOTE ME#CARRY ON LEARNINGHOPE IT HELPS3. what is the area of the given figure A.132cm B.26cmC.576cmD.132m
Answer:
A.132
Step-by-step explanation:
132
calculate
132
4. 13-15 14. In APQR, AB I QR, find the value of x.A. 4 cm B. 6 cmC. 8 cmD. 10 cm15. Which of the following must be the value of m to make XY parallel to AC?A 10 cmC. 14 cmB. 12 cmD. 16 cm16.A 9 m vertical pole casts a 5 m shadow when a tower casts a 100 m shadow. What is theheight of the tower?A. 100 mB. 180 mC. 300 mD. 900 m17. How long is the ladder which makes an angle of 300 with the side of the house and whosefoot is 104 cm away from the base of the house?A.52 √3 cmB. 102 cmC. 102 √3 cmD. 208 cm18. the perimeters of two similar triangles are 20 cm and 32 cm what is the length of the altitude of the bigger triangle if the length of the altitude of the smaller triangle is 10 cm?A.8cmB.12cmC.16cmD.22cm19.∆ABC~∆DEF .If AB = 5 ,DE =8 and the area of ∆ABC is 50 cm^2 what is the area of ∆DEF?A.58cm^2B.80cm^2C.128cm^2D.132cm^220. The altitude of the hypotenuse of a right triangle divides the hypotenuse into segments of length 4 cm and 25 cm. what is the length of the altitude?A.10cmB.21cmC.29cmD.100cmPls respect the question.If you don't know the answer,just leave.I'll MARK BRAINLIEST the correct answer.
Answer:
13. A
14. B
15. A
BRAINLIEST PLEASE
5. A rectangular block of marble has a base 936cm by 252cm, with a height of 132cm. Mr. Lim needs to cut the marble up into cubes of the largest possible size.Find the dimension of the marble cube he can cut.
Answer:
I HOPE IT'S HELP
6. The width of a rectangle is 20cm and it's perimeter is 132cm what is the area of the rectangle pa help po
Answer:
The problem of finding the area of a rectangle with a given width and perimeter is a classic example in mathematics. In this case, we are given that the width of the rectangle is 20cm and its perimeter is 132cm. To solve for the area, we need to use the formula A = lw, where A represents the area, l represents the length, and w represents the width.
Since we know that the perimeter of a rectangle is equal to twice its length plus twice its width (P = 2l + 2w), we can substitute in our values to get:
132 = 2l + 2(20)
132 = 2l + 40
92 = 2l
46 = l
Now that we have both length and width, we can plug them into our formula:
A = (46)(20)
A = 920
Therefore, the area of this rectangle is 920 square centimeters. This problem demonstrates how mathematical formulas can be used to solve real-world problems.
