Choose the coldest temperature: A -5C B12F C0C D-10C

1. Choose the coldest temperature: A -5C B12F C0C D-10C

Step-by-step explanation:

B. 12⁰F kasi 12⁰F equals to -11⁰C

2. What is the area of this triangle? A=bh2

Area= ½B×H

Hope It Helpss

3. What are the types of chemical bonding of BH2(borone)

HO² means water that is only I know I'm sorry.......(+_+)(+_+)(+_+)(+_+)

4. find the surface area of each pyramid sa=bh 2 3 bh2+ p2​

The formula for the surface area of a pyramid depends on the shape of its base. Assuming the base of the pyramid is a regular polygon, we can use the following formula:

SA = 1/2 × Perimeter of Base × Slant Height + Base Area

where SA is the surface area of the pyramid, and the slant height is the distance from the apex to the midpoint of any side of the base.

If we let b be the length of one side of the base of the pyramid, and h be the height of the pyramid (i.e., the distance from the apex to the base), then we can calculate the perimeter of the base as nb, where n is the number of sides of the base. The base area can be calculated using the formula for the area of a regular polygon, which is:

Base Area = (1/4) × n × b^2 × cot(π/n)

where cot(π/n) is the cotangent of the angle formed by two adjacent sides of the base.

With these values, we can plug them into the formula for the surface area of the pyramid:

SA = 1/2 × nb × sqrt(h^2 + (b/2)^2) + (1/4) × n × b^2 × cot(π/n)

Simplifying the expression, we get:

SA = (1/2) × nb × sqrt(4h^2 + b^2) + (1/4) × n × b^2 × cot(π/n)

So, the surface area of the pyramid is given by the formula:

SA = (1/2) × nb × sqrt(4h^2 + b^2) + (1/4) × n × b^2 × cot(π/n)

or

SA = bh/2 + (1/2) * sqrt(h^2 + (b/2)^2) * b

where SA is the surface area, b is the length of one side of the base, and h is the height of the pyramid.

Note: The formula provided in the question (sa = bh/2 + (1/3) * p^2) is the formula for the surface area of a pyramid with a triangular base, where p is the perimeter of the base. However, this formula is not applicable to pyramids with other types of bases.

5. B. Give the measure of the following angles1. FGH2. CHG3. DHE4. BHF5. BHG6. BHD7. ABC8. AHB9. DHF10. EHG ​

Answer:

Sana makatulong

Step-by-step explanation:

Next time ayusin mo mag pic para malaman ko Kong saan ako nag kulang

6. angles have special names identifying their positions with respect to the parallel lines cut by a transversal and it can been summarized as:If two parallel lines are cut by a transversal, then...IllustrationIf-then Formcorrespondingangles are congruent.If CD⃡ ║ AB⃡ , then∠CGE ≅ ∠AHG.Example:If m∠CGE = 140,then m∠AHG = 140.If CD⃡ ║AB⃡ , then∠DGE ≅ ∠BHG.Example:If m∠DGE = 40,then m∠BHG = 40.If CD⃡ ║AB⃡ , then∠CGH ≅ ∠AHF.Example:If m∠CGH = 40,then m∠AHF = 40.If CD⃡║AB⃡ , then ∠DGH ≅ ∠BHF.Example:If m∠ DGH = 140, then m∠DHF =140.alternate interiorangles are congruent.If CD⃡║AB⃡ , then ∠CGH ≅∠BHGExample:If m∠CGH = 40,then m∠BHG = 40.If CD⃡║AB⃡ , then∠DGH≅∠AHG.Example:If m∠DGH = 140,then m∠AHG = 140.alternate exteriorangles are congruent.If CD⃡║AB⃡ , then∠CGE ≅ ∠BHFExample:If m∠CGE = 140,then m∠BHF = 140.If CD⃡║AB⃡ , then∠DGE≅ ∠AHFExample:If m∠DGE = 40,then m∠AHF = 40.same-side interior angles aresupplementaryIf CD⃡║AB⃡ , then ∠CGH and∠AHG are supplementaryExample:If m∠CGH = 40,then m∠AHG = 140because they are supplementary.If CD⃡ ║AB⃡ , then ∠DGH and∠BHG are supplementary.Example:If m∠DGH = 140,then m∠BHG = 40because they are supplementary.same-side exterior angles aresupplementaryIf CD⃡ ║AB⃡ , then∠CGE and ∠AHF are supplementary.Example:If m∠CGE = 140, then m∠AHF = 40because they are supplementary.If CD⃡ ║AB⃡ , then ∠DGE and ∠BHF aresupplementary.Example:If m∠DGE = 40, then m∠BHF = 140because they are supplementary.DefinitionCorresponding angles – a pair of non-adjacent interior and exterior angles on the same side of a transversal.Alternate interior angles – a pair of non-adjacent interior angles on opposite side of a transversal.Alternate exterior angles – a pair of non-adjacent exterior angles on opposite side of a transversal.Same-side interior angles – interior angles on the same side of a transversal.Same-side exterior angles – exterior angles on the same side of a transversal.*CONGRUENT – having the same size and shape.Symbolscongruent≅angle ∠parallel ∥line ↔perpendicular ⊥Activity 3: Direction: Analyze the figure below and complete the table.QUESTIONANSWER1. Name at least 4 pairs of congruent angles.2. Name 2 pairs of alternate-interior angles.3. If m∠1 = 79, what is m∠4?4. If ∠1 and ∠7 is alternate-exterior angle, what is the relation of ∠7 to ∠8?5. If m∠6 =101, what is m∠8?6. From your answer in number 5, what is m∠3?7. What is the sum of m∠3 and m∠4?8. What is the relation between ∠3 and ∠5?9. The pair of alternate-exterior angle is ∠2 and _____.10. The m∠4 + m∠5 = ___________.​

ANSWER

1. Name at least 4 pairs of congruent angles.

∠2 and ∠6 ∠1 and ∠5∠4 and ∠8∠3 and ∠6

2. Name 2 pairs of alternate-interior angles.

∠3 and ∠5∠4 and ∠6

3. If m∠1 = 79, what is m∠4?

The answer is 101 ••••••. m∠4 = 101

4. If ∠1 and ∠7 is alternate-exterior angle, what is the relation of ∠7 to ∠8?

The relation of ∠7 to ∠8 is same side as exterior angle.

5. If m∠6 =101, what is m∠8?

m∠8 = 101

6. From your answer in number 5, what is m∠3?

m∠3 = 79

7. What is the sum of m∠3 and m∠4?

m∠3 = 79 + m∠4 = 101 = 180

8. What is the relation between ∠3 and ∠5?

The relation between ∠3 and ∠5 is alternate interior angle.

9. The pair of alternate-exterior angle is ∠2 and _____.

The pair of alternate-exterior angle is ∠2 and ∠8.

10. The m∠4 + m∠5 = ___________.

m∠4 = 101 + m∠5 = 79

so m∠4 + m∠5 = 180

MORE INFORMATION :

Corresponding angles is a pair of non-adjacent interior and exterior angles on the same side of a transversal.

Alternate interior angles is a pair of non-adjacent interior angles on opposite side of a transversal.

Alternate exterior angles is a pair of non-adjacent exterior angles on opposite side of a transversal.

Same-side interior angles is a interior angles on the same side of a transversal.

Same-side exterior angles is a exterior angles on the same side of a transversal.

CONGRUENT are having the same size and shape.

Symbols

congruent , ≅

angle , ∠

parallel , ∥

line , ↔

perpendicular , ⊥

#CarryOnLearning

7. 2. The formula for the area of a triangle is A= bh2. If the base (b) = 10 cm and the height (h) = 6 cm, what is the area of the triangle? solution and answer pls

Answer:

A= 30 sq. cm

Step-by-step explanation:

A= bh/2 (this is the correct formula)

A= (10cm)(6cm)/2

A= 60cm/2

A= 30 sq. cm or cm^2

8. Choose your answer from the options and write the letter of the answer to the space provided before each number. _____21. 3x + 5 if x = 2, what is the value of the expression? 8 c. 10 9 d. 11 _____22. Add: 4x2 – 2x +5 and 7 + 5x3 + 4x – x2. 5x3 + 3x2 + 2x + 12 c. -5x3 – 3x2 + 2x -12 5x3 + 3x2 - 2x – 12 d. 5x3 – 3x2 + 2x + 12 _____23. A box is (2x – 3) by (x + 5) by (3x + 1), what is the volume of the box if x = 3 cm? 24cm3 c. 240cm3 240cm2 d. 2400cm3 _____24. (2x+3)2, Find the Product. 6x2 + 9 c. 4x2 – 12x + 9 4x2 + 6 d. 4x2 + 12x + 9 _____25. x + 2 = 8, what is the value of x? 6 c. 10 -6 d. 16 _____26. Solve for x inequality, 2x ≤ 4. x ≤ 0 c. x ≤ 6 x ≤ 2 d. x ≤ 8 _____27. Add: (5x4 - 3x2 + 4); (6x3 – 4x2 – 7) 5x4 + 6x3 – 7x2 – 3 c. 5x4 – 6x3 + 7x2 – 3 5x4 – 6x3 – 7x2 – 3 d. 5x4 – 6x3 – 7x2 + 3 _____28. Subtract 4xy + 5x – 7y + 3 from xy – 6x + y + 6 -3xy – 11x + 8y + 3 c. 3xy + 11x + 8y + 3 3xy – 11x + 8y + 3 d. 3xy – 11x - 8y – 3 _____29. Elisse has 20 meters ribbon. How many 15 cm of ribbon can be cut from it? 123 c. 133 128 d. 138 _____30. The formula for the area of triangle is A= bh2 If the base (b) = 10 cm and the height (h) = 6cm, what is the area of the triangle? 15cm2 c. 25cm2 20cm2 d. 30cm2

parang may kulang ang 21

9. activity 10:PARTS BY PARTSDirections: refer to the given figure at the right to answer the followingQuestions:1.what do you call polygon BDFH?why?2.what appropriate name could be given to polygon ABCDEFGH?why?3.name a heptagon.4.what is diagonal?name the diagonals of BDFH?5.nme an interior point of BDFH6.name the exterior point of pentagon BCDE7.give a pair of consecutive sides of quadrilateral IFGH8.give a pair of consecutive angels of triangle BHF ​

Answer:

it wont send my answer so here is a pic

Step-by-step explanation: