fe +o2 =paki answer po pls
1. fe +o2 =paki answer po pls
Answer:
Fe+o2=Fe203
Expanation:
Fe + O2 → Fe2O3 is the unbalanced form of chemical reaction.
2. Fe(s) + O2(g) → Fe2O3(s)
4 Fe(s) + 3 O2(g) = 2 Fe2O3(s).Here is the balanced equation
3. What is the rate law equation of Fe + O2 ----------------Fe2O3
Answer:
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4. How many moles of Fe2O3 will be 27.0g of Fe, assuming O2 is available in excess
●●●●●●●●●●●●●●●●●●●●●●●●●●●●●●
0.24 moles
●●●●●●●●●●●●●●●●●●●●●●●●●●●●●●
0.24 moles of Fe2O3 will be produced from 27.0g of Fe assuming O2 is available in excess.
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Explanation:
sana makatulong ❤
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5. 1. ___ CO + ___ O2 → ___ CO2 (balanced equation) ___ g CO : ___ g O2 ___ g CO : ___ g CO2 ___ g O2 : ___ g CO2 2. ___ C + ___ H2 → ___ CH4 (balanced equation) ___ g C : ___ g H2 ___ g C : ___ g CH4 ___ g H2 : ___ g CH4 3. ___ SO2 + ___ O2 → ___SO3 (balanced equation) ___ mole SO2 : ___ mole O2 ___ mole SO2 : ___ mole SO3 ___ mole O2 : ___ mole SO3 4. ___ S8 + ___ F2 → ___ SF6 (balanced equation) ___ mole S8 : ___ mole F2 ___ mole S8 : ___ mole SF6 ___ mole F2 : ___ mole SF6 5. ___ Mg +___ Fe2O3 → ___ Fe + ___ MgO (balanced equation) ___ mole Mg : ___ Fe2O3 ___ mole Mg : ___ mole Fe ___ mole Fe2O3 : ___ mole Fe ___ mole Fe2O3 : ___ mole MgO ___ mole Fe : ___ mole MgO
First report me
[tex]\blue{ \rule{500pt}{300000pt}}[/tex]
6. III. Engagement:Task #2: Use coefficient to balance the following equations.1.H2 + O2H2O2. ZnZn +HCI- ZnCl2ZnCl2 +He3. _Al +Fe(NO3)2AKNO3)3+Fe4. _NaNO3NaNO2 + O25. CHA+O2►CO2 + __H20
Correct me if im wrong
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thank you
7. Given the following reaction: 4Fe + 3O2 -------> 2Fe2O3 How many moles of Fe will be produced when 50 grams of O2 is reacted?
nalito ako bakit Fe produced. Is it Fe needed to produce Fe2O3, or Fe2O3 produced per 50g O2?
8. Find there Chemical Reactions 1.) CH4+O2=>CO2+H20 2.) Fe+CuSo4=>Cu+FeSO4 3.) P4+O2=>P2O5 Pahelp po ako genchem po
CHEMICAL REACTIONSLaw of Conversion of Mass
— This law of mass states that no atoms can be created or destroyed in chemical reaction. The atoms in the reactants have to balance the number of atoms in the product.
We need to compare the number of atoms for each element on both sides of an equation, then change coefficient so the number is same.
1.) [tex] \bold{CH_4 + O_2 \implies CO_2 + H_2 O\implies\: CH_4 + 2O_2 \implies CO_2 2H_2O}[/tex]
As we can see that C is balanced.
So, to balance H multiply the H20 on the right by 2.
[tex] CH_4 + O_2 \implies CO_2 + 2H_2 O[/tex]Now, To balance O we need to multiply O2 on the right by 2.
[tex] CH_4 + 2O_2 \implies CO_2 + 2H_2O[/tex]2.) [tex] \bold{Fe + CuSO_4 \implies Cu+FeSO_4 \implies Fe + CuSO_4 \implies Cu+FeSO_4}[/tex]
The given equation is already balanced. We can see Fe, Cu, S, and O are balanced so you don't have to worry how to balance this. But if you want to make sure the equation is balanced, we can solve this algebraicly :)
[tex] Fe+CuSO_4\implies Cu+FeSO_4[/tex]
[tex] vFe+vCuSO_4\implies wCu+ tFeSO_4[/tex]
As you can see I add some variables in the equation because we're going to use the variables to create a system of equation to find the coefficient.
[tex] \begin{cases} Fe:\:u=t\\ Cu:\:v=w\\ S:\:v=t\\ O:\:4v=4t\\\end{cases}[/tex][tex]\begin{cases} u=t\\v=w\\v=t\\4v=4t\\\end{cases}[/tex]
[tex] \begin{cases} u=t\\w=t\\4w=4t\\\end{cases}[/tex]
[tex] \begin{cases} u=t\\4w=4t\\\end{cases}[/tex]
[tex] \begin{cases} 4t=4t\end{cases}[/tex]
Gather all the coefficient then select an arbitrary coefficient: t = 1
(Note: We must ensure that all coefficients are an integers)
[tex] \boxed{u = 1,\:v=1,\:w=1,\:t=1}[/tex]
Therefore, [tex] Fe + CuSO_4 \implies Cu+FeSO_4[/tex]
3.) [tex] \bold{P_4+O_2\implies P_2O_5 \implies P_4+5O_2 \implies 2P_2O_5}[/tex]
This equation is similar to the item #1.
So, To balance P just multiply P2O5 on the right by 2. Therefore,
[tex] P_4 + O_2 \implies 2P_2O_5[/tex]After that, we need to balance the O just multiply O2 on the right by 2. Therefore,
[tex] P_4+5O_2 \implies 2P_2O_5[/tex][tex]\\\\\\[/tex]
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9. C. Balanced the given equations.1.) Fe + H20 Fe,04 + H22.) Cl2 + HBO HCI + Br23.) C2H2 + O2 CO2 + H2O
Answer:
these are the balanced equations
1. Fe + 4 H2O = FeO4 + 4 H2
2. 2 HBr + Cl2 = 2 HCl + Br2
3. 2 C2H2 + 5 O2 = 4 CO2 + 2 H2O
______________________________________
2.) Cl2 + HBO HCI + Br2
is that really HBO? in balancing for number 2, instead of HBO , i used HBr since Br is present in the productsit is impossible kasi to balance the equation if elements in the reagents are not present in the products, like B and O.let me know.
10. A. Balance the following chemical equations. 1. Fe + O2 → Fe3O4
Answer:
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11. How many moles of Fe are needed for the reaction of 12. 0 moles O2?.
Answer:
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Spicy hotdogs my tommy is In The center of the bread
Explanation:
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12. In the formation of iron (II) oxide, which species is being reduced? Fe(s) + O2(g) → FeO(s) a.FeO b.Fe2O3 c.Fe d.O2
Answer:
B.Fe203
Explanation:
yun ang alam ko
13. Table 2: Chemical Equations Chemical Equation Chemical Reaction Fe + CuSO4 - Fe SO4 + Cu Example: Single Displacement 1. Al + O2 Al2O3
Answer:
We will take the given equation: Al + O2 --> Al2O3. We can see that this is not balanced – there is 1 aluminum on the reactant side and 2 on the product side, and there are 2 oxygens on the reactant side and 3 on the product side.
14. Fe + O2+ H2O - > Fe (OH) 3 prove the reaction to law conservation of mass with solution
Answer:
According to law of conservation of mass, Total mass of reactants = Total mass of products. Here, baking soda mixture (reactant) on heating gives solid residue and carbon dioxide ( products).
Explanation:
That was correct because this is my answer in my previous task...hope it will help you :)
15. balance de ecuaciones utilizando el metodo de tanteo P+O2 P2O3KCIO3 KCI+O2Fe+HCI FeCl3+H2
Instrucciones sobre ecuaciones químicas de balance:
Introduzca una ecuación de una reacción química y haga clic en "Balance". La respuesta aparecerá a continuación
Utilice siempre la caja superior para el primer carácter en el nombre de elemento y la caja inferior para el segundo carácter. Ejemplos: Fe, Au, Co, Br, C, O, N, F. Comparar: Co - cobalto y CO - monóxido de carbono
Para introducir un electrón en una ecuación química use {-} o e
Para introducir un ión especifique la carga después del compuesto en corchetes rizados: {+3} o {3+} o {3}.
Ejemplo: Fe{3+} + I{-} = Fe{2+} + I2
Sustituir grupos inmutables en compuestos químicos para evitar ambigüedad.
Por ejemplo, no se equilibrará la ecuación C6H5C2H5 + O2 = C6H5OH + CO2 + H2O,
Pero PhC2H5 + O2 = PhOH + CO2 + H2O
No se requieren estados compuestos [como (s) (aq) o (g)].
Si no sabe qué productos están ingresando sólo reactivos y haga clic en "Balance". En muchos casos se sugerirá una ecuación completa.
La estequiometría de reacción podría calcularse para una ecuación equilibrada. Indíquese el número de lunares o el peso de uno de los compuestos para calcular el resto.
El reactivo límite puede calcularse para una ecuación equilibrada introduciendo el número de lunares o peso para todos los reactivos.
16. Balance the following equation. 1. Al + N2 → AlN2. Fe + O2 → Fe3O43. CaCO3 → CaO + CO2
Answer:
1. 2AL + N2 → 2ALN
2.balance napo sya
3.nasa pic po pakiclick nalang po
Explanation:
hope its help toyou
correct me if im wrong
brainliest?
17. Balance the following chemical reaction1.P4+O4→P2+O52.Zn+HCl→ZnCl2+H23.Fe+NaBr→FeBr3+Na4.Al+O2→Al2O35.NaNO3→NaNO2+O2
Answer:
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18. 1. Fe + Cl2 → FeCl32. Fe + O2 → Fe2O33. FeBr3 + H2SO4 → Fe2(SO4)3 + HBr4. C4H6O3 + H2O → C2H4O25. C2H4 + O2 → CO2 + H2O6. C4H10O + O2 → CO2 + H2O7. H2SiCl2 + H2O → H8Si4O4 + HCl8. NH3 + O2 → NO + H2O9. KOH + H3PO4 → K3PO4 + H2O10. Al + O2 → Al2O311. CH4 + O2 → CO2 + H2O12. N2 + H2 → NH313. Al + HCl → AlCl3 + H214. Zn + HCl → ZnCl2 + H215. N2 + O2 + H2O → HNO3Please! answers this immediately
Answer:
1.PA+02
p2+0s
2.Zn+HCI
ZnCI2+H2
3.Fe+NaBr
Febr+Na
4.Al+02
Al02
5.Nano
Nano2+08
Explanation:
pasensya napo ito lng alam Kong sagot ehhh
19. which of the following equation is balanced?a. Fe + O2 = Fe2O3b.NaOH + HCI = NaCI + H2O
Answer:
ANSWER
A. Fe + O2 = Fe 2O3
Ayun po sagot ko sana makatulong
20. how do you balance this chemical equation Fe + O2 -> Fe2O3
Answer:
Fe + O2 → Fe2O3 is the unbalanced form of chemical reaction.
Balancing the simple molecules first, in this case the O2
Fe + 3O2→ Fe2O3 there are now 6 O atoms on the left, there must also be 6 O atoms on the right.
Fe + 3O2 → 2Fe2O3
Balance the rest of the equation.
4Fe + 3O2→ 2Fe2O3
Explanation:
21. 8. C₂H₂ + O₂ → CO₂ + H₂O29. Fe + H₂O → H₂ + Fe₂O410. Al + O₂ → Al₂O3balance the equation follow the law of conservation mass
Explanation:
yung kompleto sana para malinawn ako
yan po yung sagot
sana makatulong
22. Balance the following chemical equations. a) Fe + O2 - - > Fe203b) H2 +Cl2 - - > HCIc) Ag + H2S - - >Ag2S + H2d) CH4 + O2 - - > CO2 + H2Oe) HgO - - > Hg + O2
Explanation:
Balance the following chemical equations.
Balance the following chemical equations. a) Fe + O2 - - > Fe203
Balance the following chemical equations. a) Fe + O2 - - > Fe203b) H2 +Cl2 - - > HCI
Balance the following chemical equations. a) Fe + O2 - - > Fe203b) H2 +Cl2 - - > HCIc) Ag + H2S - - >Ag2S + H2
Balance the following chemical equations. a) Fe + O2 - - > Fe203b) H2 +Cl2 - - > HCIc) Ag + H2S - - >Ag2S + H2d) CH4 + O2 - - > CO2 + H2O
Balance the following chemical equations. a) Fe + O2 - - > Fe203b) H2 +Cl2 - - > HCIc) Ag + H2S - - >Ag2S + H2d) CH4 + O2 - - > CO2 + H2Oe) HgO - - > Hg + O2
23. 5. N₂ + O₂ + H₂O → HNO3 O2 6. P4+ O2 → P2O5 7. NaNO3 → NaNO₂ + O₂ 8. C3H8+ O2 → CO₂ + H₂O 9. Fe + H₂O → H₂+ Fe3O4 10. Al + O₂ → Al₂O3
Answer:
no answer needed because you already know the answer
Explanation:
Answer:
yes wot is this
Explanation:
-_-dude your too smart
24. how many moles of Fe are needed for the reaction of 12.0 moles O2?
Answer:
16.00 moles of Fe
Explanation:
Initial moles of oxygen reactant(given)= 12.0 mol
iron and oxygen reactants combine in a 4:3 moral ratio.
initial moles of iron reactants =
[tex] \frac{4}{3}x12.0 \: mol = 16.0 \: mol[/tex]
25. Balance the following chemical reactions.1. _____ C3H8 + _____ O2 → _____CO2 + _____ H2O2. _____ Al + _____ Fe3N3 → ____ AlN + _____ Fe3. _____ Na + _____ Cl2 → _____ NaCl4. _____ H2O2 → _____ H2O + _____ O25. _____ C6H12O6 + _____ O2 → _____ H2O + _____ CO2
Answer:
1. C3H8 + 502 ----> 3CO2 + 4H20
2. 2Al + Fe3N2 → 2AlN + 3Fe
3. 3Al + Fe3N3 → 3AlN + 3Fe
4. 2H2O2 → 2H2O + O2
5. C6H12O6 + 6O2 → 6H2O + 6CO2
Explanation: I used chemical equation balancer hope it helps. :>
26. If there are 1.25 moles of Fe and 1.25 moles of O2, How many moles of Fe2O3 will be produced? What is the mass?
Answer:
Hoe many moles of Fe203 will be produced? The answer is: 1 mole
What is the mass?
The answer is: 159.69 g/mol
27. CO tions: Balance the following chemical equations. 1. Zn + HCl → ZnCl2 + H2 2. CH4 +02 →C02 + H20 3. Fe + NaBr → FeBr3+ Na 4. SICIA + H2O + SIO2 + HCI 5. N2 + O2 + H20 → HNO3 3 6. P4+02 → P205 7. NaNO3 → NaNO2 +02 8. C3H8 + O2 + CO2 + H20 9. Fe + H20 > H2+ Fe304 10. Al + O2 → Al203
BALANCE THE FOLLOWING EQUATION:
ANSWER:
1. Zn + 2HCl → ZnCl2 + H2O
2. CH4 + 2O2 → CO2 + 2H2O
3. Fe + 3NaBr → FeBr3 + 3Na
4. SiCl4 + 2H2O → SiO2 + 4HCl
5. 2N2 + 5O2 + 2H2O → 4HNO3
6. P4 + 5O2 → 2P2O5
7. 2NaNO3 → 2NaNO2 + O2
8. C3H8 + 5O2 → 3CO2 + 4H2O
9. 3Fe + 4H2O → Fe3O4 + 4H2
10. 4Al + 3O2 → 2Al2O3
28. Balanced the given chemical equations then identify the reactants and the products 1. N205 > N2 + O2 2. KCIO3 →KCI + O2 3. NaO + H2O NaOH 4. CH4 + O2 CO2 + H2O 5. Fe + O2 → Fe2O3 Balanced chemical equation Reactants Products
Answer:
1. N2O5 = N2 + O2
Reactants = Products
2 N2O5 = 2 N2 + 5 O2 (balanced equation)
2. KCIO3 = KCI + O2
Reactants = Products
2 KCIO3 = 2 KCI + 3 O2 (balanced equation
3. NaO + H2O = NaOH + O2
Reactants = Products
4 NaO + 2 H2O = 4 NaOH + O2 (balanced equation)
4. CH4 + O2 = CO2 + H2O
Reactants = Products
CH4 + 2 O2 = CO2 + 2 H2O (balanced equation)
5. Fe + O2 = Fe2O3
Reactants = Products
4 Fe + 3 O2 = 2 Fe2O3 (balanced equation)
_______________________________________________________
Note:
Reactants are on the left side and the Products are on the right side.
_______________________________________________________
please comment down about your number 3 product, I am a bit confused.
if your number 3 is this
NaO + H2O = NaOH + OH, then there is no need to balance since, this is already a balanced equation.
29. TRY: balance and identify the type of chemical reaction 1. C6H12 + O2 CO2 + H2O 2. Fe2O3 + C Fe + CO2 3. Fe + HC2H3O2 Fe(C2H3O3)3 + H2 4. Pb + H3PO4 H2 + Pb3(PO4)2 5. (NH4)2Cr2O7 Cr2O3 + N +H2O
C6H12 + 9O2 → 6CO2 + 6H2O
Hexenes + Dioxygen = Carbon Dioxide + Water
Reaction Type
Combustion
Reactants
Hexenes - C6H12
Hexene C6H12 Molar Mass C6H12 Oxidation Number
Dioxygen - O2
Lox O₂ Oxygen Oxygen Gas Liquid Oxygen Triplet Oxygen Diatomic Oxygen Molecular
the answer is in the pictures, hope you can understand those scribbles Hindi kasi ako gumagamit ng mesa
30. Fe(s) + O2(g) → Fe,0(#)(Molar mass: Fe:55.9, 0:16)a. Write the balanced equation of the reaction,b. What is the mole-mole ratio of Fe to Fe2O ?c. How many moles of Fe2O3 is produced from 39,4 moles of Fe?d. What is the molar mass of Fezos?e. How many grams of O2 are needed to produce 29.8 g of Fe,0,?
716+383783 needed. fezos proud of you for the update and I will be buy
6283actually need anything else please let728 number is the answer
