Ag3po4 Compound Name

Ag3po4 Compound Name

Chemical Name of Ag3PO4​

1. Chemical Name of Ag3PO4​


Answer:

Your mom

Explanation:


2. B. Solve the percentage composition of all atorns in compound1. AICI32. K2O3. NaBr4. Zn(OH)25. Ag3PO4​


Solution (1)

Step 1: Calculate the molar mass of AlCl₃.

molar mass = (26.98 g/mol × 1) + (35.45 g/mol × 3)

molar mass = 133.33 g/mol

Step 2: Calculate the percentage composition of the elements in AlCl₃.

For %Al

[tex]\text{\%Al} = \frac{\text{26.98 g/mol × 1}}{\text{133.33 g/mol}} × 100[/tex]

[tex]\boxed{\text{\%Al = 20.24\%}}[/tex]

For %Cl

[tex]\text{\%Cl} = \frac{\text{35.45 g/mol × 3}}{\text{133.33 g/mol}} × 100[/tex]

[tex]\boxed{\text{\%Cl = 79.76\%}}[/tex]

Solution (2)

Step 1: Calculate the molar mass of K₂O.

molar mass = (39.10 g/mol × 2) + (16.00 g/mol × 1)

molar mass = 94.20 g/mol

Step 2: Calculate the percentage composition of the elements in K₂O.

For %K

[tex]\text{\%K} = \frac{\text{39.10 g/mol × 2}}{\text{94.20 g/mol}} × 100[/tex]

[tex]\boxed{\text{\%K = 83.01\%}}[/tex]

For %O

[tex]\text{\%O} = \frac{\text{16.00 g/mol × 1}}{\text{94.20 g/mol}} × 100[/tex]

[tex]\boxed{\text{\%O = 16.99\%}}[/tex]

Solution (3)

Step 1: Calculate the molar mass of NaBr.

molar mass = (22.99 g/mol × 1) + (79.90 g/mol × 1)

molar mass = 102.89 g/mol

Step 2: Calculate the percentage composition of the elements in NaBr.

For %Na

[tex]\text{\%Na} = \frac{\text{22.99 g/mol × 1}}{\text{102.89 g/mol}} × 100[/tex]

[tex]\boxed{\text{\%Na = 22.34\%}}[/tex]

For %Br

[tex]\text{\%Br} = \frac{\text{79.90 g/mol × 1}}{\text{102.89 g/mol}} × 100[/tex]

[tex]\boxed{\text{\%Br = 77.66\%}}[/tex]

Solution (4)

Step 1: Calculate the molar mass of Zn(OH)₂.

molar mass = (65.39 g/mol × 1) + (16.00 g/mol × 2) + (1.008 g/mol × 2)

molar mass = 99.406 g/mol

Step 2: Calculate the percentage composition of the elements in Zn(OH)₂.

For %Zn

[tex]\text{\%Zn} = \frac{\text{65.39 g/mol × 1}}{\text{99.406 g/mol}} × 100[/tex]

[tex]\boxed{\text{\%Zn = 65.78\%}}[/tex]

For %O

[tex]\text{\%O} = \frac{\text{16.00 g/mol × 2}}{\text{99.406 g/mol}} × 100[/tex]

[tex]\boxed{\text{\%O = 32.19\%}}[/tex]

For %H

[tex]\text{\%H} = \frac{\text{1.008 g/mol × 2}}{\text{99.406 g/mol}} × 100[/tex]

[tex]\boxed{\text{\%O = 2.03\%}}[/tex]

Solution (5)

Step 1: Calculate the molar mass of Ag₃PO₄.

molar mass = (107.87 g/mol × 3) + (30.97 g/mol × 1) + (16.00 g/mol × 4)

molar mass = 418.58 g/mol

Step 2: Calculate the percentage composition of the elements in Ag₃PO₄.

For %Ag

[tex]\text{\%Ag} = \frac{\text{107.87 g/mol × 3}}{\text{418.58 g/mol}} × 100[/tex]

[tex]\boxed{\text{\%Ag = 77.31\%}}[/tex]

For %P

[tex]\text{\%P} = \frac{\text{30.97 g/mol × 1}}{\text{418.58 g/mol}} × 100[/tex]

[tex]\boxed{\text{\%P = 7.40\%}}[/tex]

For %O

[tex]\text{\%O} = \frac{\text{16.00 g/mol × 4}}{\text{418.58 g/mol}} × 100[/tex]

[tex]\boxed{\text{\%O = 15.29\%}}[/tex]

#LearnMore


3. B. Solve the percentage composition of all atoms in a compound1. AICI32. K203. NaBr4. Zn(OH)25. Ag3PO4​


Solution (1)

Step 1: Calculate the molar mass of AlCl₃.

molar mass = (26.98 g/mol × 1) + (35.45 g/mol × 3)

molar mass = 133.33 g/mol

Step 2: Calculate the percentage composition of AlCl₃.

For mass percent of Al

[tex]\text{mass percent of Al} = \frac{\text{26.98 g/mol × 1}}{\text{133.33 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of Al = 20.24\%}}[/tex]

For mass percent of Cl

[tex]\text{mass percent of Cl} = \frac{\text{35.45 g/mol × 3}}{\text{133.33 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of Cl = 79.76\%}}[/tex]

Solution (2)

Step 1: Calculate the molar mass of K₂O.

molar mass = (39.10 g/mol × 2) + (16.00 g/mol × 1)

molar mass = 94.20 g/mol

Step 2: Calculate the percentage composition of K₂O.

For mass percent of K

[tex]\text{mass percent of K} = \frac{\text{39.10 g/mol × 2}}{\text{94.20 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of K = 83.01\%}}[/tex]

For mass percent of O

[tex]\text{mass percent of O} = \frac{\text{16.00 g/mol × 1}}{\text{94.20 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of O = 16.99\%}}[/tex]

Solution (3)

Step 1: Calculate the molar mass of NaBr.

molar mass = (22.99 g/mol × 1) + (79.90 g/mol × 1)

molar mass = 102.89 g/mol

Step 2: Calculate the percentage composition of NaBr.

For mass percent of Na

[tex]\text{mass percent of Na} = \frac{\text{22.99 g/mol × 1}}{\text{102.89 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of Na = 22.34\%}}[/tex]

For mass percent of Br

[tex]\text{mass percent of Br} = \frac{\text{79.90 g/mol × 1}}{\text{102.89 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of Br = 77.66\%}}[/tex]

Solution (4)

Step 1: Calculate the molar mass of Zn(OH)₂.

molar mass = (65.39 g/mol × 1) + (16.00 g/mol × 2) + (1.008 g/mol × 2)

molar mass = 99.41 g/mol

Step 2: Calculate the percentage composition of Zn(OH)₂.

For mass percent of Zn

[tex]\text{mass percent of Zn} = \frac{\text{65.39 g/mol × 1}}{\text{99.41 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of Zn = 65.78\%}}[/tex]

For mass percent of O

[tex]\text{mass percent of O} = \frac{\text{16.00 g/mol × 2}}{\text{99.41 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of O = 32.19\%}}[/tex]

For mass percent of H

[tex]\text{mass percent of H} = \frac{\text{1.008 g/mol × 2}}{\text{99.41 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of H = 2.03\%}}[/tex]

Solution (5)

Step 1: Calculate the molar mass of Ag₃PO₄.

molar mass = (107.9 g/mol × 3) + (30.97 g/mol × 1) + (16.00 g/mol × 4)

molar mass = 418.7 g/mol

Step 2: Calculate the percentage composition of Ag₃PO₄.

For mass percent of Ag

[tex]\text{mass percent of Ag} = \frac{\text{107.9 g/mol × 3}}{\text{418.7 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of Ag = 77.31\%}}[/tex]

For mass percent of P

[tex]\text{mass percent of P} = \frac{\text{30.97 g/mol × 1}}{\text{418.7 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of P = 7.40\%}}[/tex]

For mass percent of O

[tex]\text{mass percent of O} = \frac{\text{16.00 g/mol × 4}}{\text{418.7 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of O = 15.29\%}}[/tex]

#CarryOnLearning


4. Activity 5: Know my percentage!A. Solve the percentage composition of an underlined atom being asked in a compound.1. Na2S2. Fe(OH)23. CaSO44. Al(HCO3)35. Zn(ClO2)2B. Solve the percentage composition of all atoms in a compound1. AlCl32. K2O3. NaBr4. Zn(OH)25. Ag3PO4​


Answer:

Hopefully, makatulong to sa pag-aaral niyo. ❤️

A. Solve the Underlined words

1. Na2S

% age of Na= Molar Mass of Na x Subscript of Na/Molar Mass of Na2S x 100

= 23 g of Na x 2 Numbers of Na/(23 g of Na x 2)+ (32g of S x 1) x 100

= 46 g Na/78 g Na2S x 100

= 0.589 x 100

= 58.9% of Na

2. Fe(OH)2

% age of O= Molar Mass of O x Subscript of O/Molar Mass of Fe(Oh)2 x 100

= 16 g of Fe x 2 Number/s of Fe/(56 g of Fe x 1)+(16 g of O x 2)+(1 g of H x 2) x 100

= 32 g O/90 g Fe(OH)2 x 100

= 0.355 x 100

= 35.5% of O

3. CaSO4

% age of Ca= Molar Mass of Ca x Subscript of Ca/Molar Mass of CaSO4 x 100

= 40 g of Ca x 1 Number of Ca/(40 g of Ca x 1)+(31 g of S x 1)+(16 g of O x 4) x 100

= 40 g Ca/136 g CaSO4 x 100

= 0.294 x 100

= 29.4 % of Ca

4. Al (HCO3)3

% age of H= Molar Mass of H x Subscript of H/Molar Mass of Al (HCO3)3 x 100

= 1 g of H x 3 Number/s of H/(27 g of Al x 1)+(1 g of H x 3)+(12 g of C x 3)+ (48g of O x 3) x 100

= 3 g Al/210 g Al (HCO3)3 x 100

= 0.014 x 100

= 1.4 % of H

5. Zn(ClO2)2

% age of O= Molar Mass of O x Subscript of O/Molar Mass of Zn(ClO2)2 x 100

= (16 g of O x 2) x 2 Number/s of O/(65 g of Zn x 1)+(35 g of Cl x 2)+(32 g of O x 2) x 100

= 32 g of O x 2 Numbers of O/(65 g of Zn x 1)+(35 g of Cl x 2)+(32 g of O x 2) x 100

= 64 g O/199 g Zn(ClO2)2 x 100

= 0.322 x 100

= 32.2 % of O

B.

1. AlCl3

% age of Al= Molar Mass of Al x Subscript of Al/Molar Mass of AlCl3 x 100

= 27 g of Al x 1 Number of Al/(27 g of Al x 1)+(35 g of Cl x 3) x 100

= 27 g Al/132 g AlCl3 x 100

= 0.204 x 100

= 20.4 % of Al

% age of Cl= Molar Mass of Cl x Subscript of Cl/Molar Mass of AlCl3 x 100

= 35 g of Cl x 3 Number/s of Cl/(27 g of Al x 1)+(35 g of Cl x 3) x 100

= 105 g Cl/132 g AlCl3 x 100

= 0.795 x 100

= 79.5 % of Cl

Total Percentage:

Al = 20.4%

Cl =+ 79.5%

= 99.9% or 100%

2. K2O

% age of K= Molar Mass of K x Subscript of K/Molar Mass of K2O x 100

= 39 g of K x 2 Number/s of K/(39 g of Al x 2)+(16 g of O x 1) x 100

= 78 g K/94 g K2O x 100

= 0.829 x 100

= 82.9 % of K

% age of O= Molar Mass of O x Subscript of O/Molar Mass of K2O x 100

= 16 g of K x 1 Number of O/(39 g of Al x 2)+(16 g of O x 1) x 100

= 16 g O/94 g K2O x 100

= 0.170 x 100

= 17.0 % of O

Total Percentage:

K = 82.9%

O =+ 17.0%

= 99.9% or 100%


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