Which do you think will have a higher boiling and melting point - calcium iodide or barium iodide? Why?
1. Which do you think will have a higher boiling and melting point - calcium iodide or barium iodide? Why?
Answer:
Barium iodide
Explanation:
Barium iodide has 2,027 °C
Image result for what is the boiling point of barium iodide
Melting point: 711 °C
Density: 5.15 g/cm³
Barium iodide is an inorganic compound with the formula BaI₂. The compound exists as an anhydrous and a hydrate, both of which are white solids. When heated, hydrated barium iodide converts to the anhydrous salt. The hydrated form is freely soluble in water, ethanol, and acetone.
2. what is polarity of hydrogen iodide
Answer:
the quality or condition inherent in a body that exhibits opposite properties or powers in opposite parts or directions or that exhibits contrasted properties or powers in contrasted parts or directions : the condition of having poles. 2 : attraction toward a particular object or in a specific directions
thanks me later.
Answer:
non-polar
Explanation:
all heteronuclear diatomic moleculos are non-polar
3. (3 points) Having 50.0 mL of silver nitrate solution react with excess hydrogen iodide gas yields 2.35 grams of silver iodide. What is the concentration (in M) of the silver nitrate solution?
Answer:
0.2 M Silver nitrate solution
Explanation:
AgNO3 + HI ⇌ AgI + HNO3
*AgNO3 = Silver nitrate
HI = Hydrogen Iodide
AgI = Silver Iodide
HNO3 = Nitric acid
Given:
Volume of AgNO3 = 50mL
Mass of AgI = 2.35g
Solution:
M= mole of solute(AgNO3)/L solution
since we have the volume of AgNO3, we want to get the number of moles of AgNO3 from the mass of AgI that was yield.
Conversion of the volume of AgNO3= 50mL/1000 = 0.05L
Solving for the mole of AgNO3:
mass of AgI * (1/molecular weight of AgI) = mol AgI
(2.35g AgI)* (1/234.77g/mol) AgI = 0.0100 mol AgI
*From the chemical reaction we can see that 1 mole of AgNO3 yields 1 mole of AgI
mol AgI* (1 mol AgNO3 / 1 mol AgI) = mol AgNO3
0.0100 mol AgI * (1 mol AgNO3 / 1 mol AgI) = 0.0100 mol AgNO3
Solving for the concentration of Silver nitrate solution (M):
M= mole of solute(AgNO3)/L solution
M= 0.0100 mol AgNO3 / 0.05 L solution
M= 0.2 mol/L Silver Nitrate solution
4. Having 50.0 mL of silver nitrate solution react with excess hydrogen iodide gas yields 2.35 grams of silver iodide. What is the concentration (in M) of the silver nitrate solution?
Answer:
0.200 M
Explanation:
Molarity = moles / Liter. The question has 50.0 mL as the given volume of AgNO3 which leaves the mol of AgNO3 as unknown. To determine the moles of AgNO3, we need to set up a balanced equation for the reaction.
The reaction proceeds as follows:
AgNO3 + HI → AgI + HNO3
There is a 1:1 correspondence between the Ag+ of AgNO3 and AgI according to the balanced equation. This means that the all Ag+ from AgNO3 is used up to make AgI. The I- is in excess which makes things easier for us. By computing the moles of AgI, we can determine the moles of AgNO3.
[tex]\frac{2.35g}{234.77 g/mol} = 0.0100 mol[/tex]
And by converting the volume from mL to L:
[tex]\frac{0.0100mol}{50mL*\frac{1L}{1000mL} } = 0.200 M[/tex]
Hope this answered your question!
5. some organic compounds have no hydrogen. which of the organic compounds has no hydrogen? A.ethane B.alkanes C.carbon dioxide D.hydrogen iodide
Letter C is the answer
Explanation:
That's the answer
6. According to the following reaction, how many moles of hydrogen iodide will be formed upon the complete reaction of 0.771 moles hydrogen gas with excess iodine?
Answer:
n HI = 1.542 mol
Explanation:
Write the balanced chemical equation.
H2 + I2 → 2HI
Solve for the number of moles of HI formed.
n HI = 0.771 mol H2 × (2 mol HI / 1 mol H2)
n HI = 1.542 mol
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7. the boiling point of water is greater than hydrogen sulfide because of
Answer:
Knowing that hydrogen bonds are stronger than dipole-dipole forces, this leads to : water has a higher boiling point than hydrogen sulfide because hydrogen bonds are much stronger than dipole-dipole bonds.
Explanation:
Answer:
H-bonding
Explanation:
sana makatulong po hehe
8. Write the formula for the following convalent compounds: 1. Antimony Tribromine 2. Hexaboron Silicide 3. Chlorine Dioxide 4. Hydrogen Iodide 5. Iodide Pentafluoride 6. Dinitrogen trioxide 7. Ammonia 8. Phosphorus Triiodide
Explanation:
nasa picture napo ang answer
hope it helps
9. lithium chloride or hydrogen chloride which have high boiling point
lithium chloride has higher boiling point
10. what is the different between in polar/non polar for hydrogen iodide
Answer:
Hydrogen iodide is a diatomic molecule formed by a covalent bond. The electronegativity of hydrogen is about 2.2 while iodine has an electronegativity of about 2.66. When the difference in electronegativity in a bond is between 0.5 and 1.7, the bond is usually formed from a polar covalent bond.
Explanation:
#CARRYONLEARNINGAnswer:
yes because it's a particularly
11. "I experimented on determining the boiling point of two different gases. The first one is the hydrogen gas (H2) and the other is the Ammonia gas (NH3). The result showed that the hydrogen gas has a lower boiling point compared to the ammonia gas.
Answer:
Nasaan po yung tanong???
Answer:
Ammonia gas is hydrogen gas boiling point
12. According to the following reaction, how many moles of hydrogen iodide will be formed upon the complete reaction of 0.832 moles hydrogen gas with excess iodine?
Answer:
278.9 moles you can solve it through its formula.
13. how does the hydrogen Bonding affect boiling point of liquid
Answer:
Molecules with hydrogen bonds will always have higher boiling points than similarly sized molecules which don't have an an -O-H or an -N-H group. The hydrogen bonding makes the molecules "stickier," such that more heat (energy) is required to separate them.
Answer:
Molecules with hydrogen bonds will always have higher boiling points than similarly sized molecules which don't have an an -O-H or an -N-H group. The hydrogen bonding makes the molecules "stickier," such that more heat (energy) is required to separate them.Ago 21, 2020
Explanation:
hope its help
14. write the balance1.hydrogen gas + iodine gas - hydrogen iodide.2. aqueous phosphoric acid + aqueous ammonia - aqueous ammonium phosphate.
1. H₂ (g) + I₂ (g) → 2HI (g)
2. H₃PO₄ (aq) + 3NH₃ (aq) → (NH₄)₃PO₄ (aq)
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15. The elements of group 5A, the nitrogen family, form compounds with hydrogen having the given table of boiling points. Ammonia, NH3, does not follow the downward trend in boiling point because of
Answer:
The strength of IMFA is determined by how well-separated the charges are in the compound. The strongest among the listed forces is ion-dipole with an ion being fully positive or negative. This is followed by hydrogen bonding since a large electronegativity difference between H and the atoms N, O, or F is present making it a special type of dipole-dipole force. H-bonding is followed by dipole-dipole in terms of strength and then London dispersion force, the weakest.
Explanation:
paki brainliest po
16. According to the following reaction, how many moles of hydrogen iodide will be formed upon the complete reaction of 0.771 moles hydrogen gas with excess iodine?
Answer:
n HI = 1.542 mol
Explanation:
Write the balanced chemical equation.
H2 + I2 → 2HI
Solve for the number of moles of HI formed.
n HI = 0.771 mol H2 × (2 mol HI / 1 mol H2)
n HI = 1.542 mol
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17. A substance capable of hydrogen bonding has a ____________ boiling point than a similar substance that doesn’t hydrogen bond.
#BrainlyFast
A substance capable of hydrogen bonding has a ____________ boiling point than a similar substance that doesn’t hydrogen bond.
A substance capable of hydrogen bonding has a Higher boiling point than a similar substance that doesn’t hydrogen bond.Hydrogen bond is the type of bond in which water molecule are bonded together. Water has a higher boiling point so that the hydrogen bond will bot be easily separated. Water have a higher boiling point making more attraction of hydrogen bond.
For more information, kindly visit the link below:
brainly.ph/question/2629996
18. What effect does hydrogen bonding have on the boiling point of water? Explain.
Answer:
sa na makatulong po pa brainliest and pa follow po
19. Ammonium iodide dissociates reversibly to ammonia and hydrogen iodide. NH4I(s) ↔ NH3(g) + HI(g) At 400°C, Kp = 0.81. Calculate the partial pressure of ammonia at equilibrium when a sufficient quantity of ammonium iodide is heated to 400°C.
Answer:
Wala Po Bago lang ako di ko Po alam to
Explanation:
sorry
20. 3. Which has the lowest boiling point?A. Diamond chipB. Potassium iodideC. Salt solutionD. Plain water
Answer:
diamond chip
Explanation:
kase para Ito sa ikakabuti mo
Answer:
b . potassium iodide
Sana makatulong
21. (3 points) How many liters will 0.20 mol of hydrogen iodide at 300 K and 100.0 kPa occupy? Use R = 8.314 kPa*L/(K*mol) = 0.08205 atm*L/(mol*K
Answer:
4.9884 Liters of hydrogen iodide
Explanation:
Assuming ideal gas law applies, our working equation would be PV=nRT where P is the pressure, V will be the volume, n will be the number of moles, R is the gas constant (which is given in the problem), and T is the temperature.
The problem asks for the number of liters which means we need the volume. Rearranging the equation to get the volume, our final working equation will be V=[tex]\frac{nRT}{P}[/tex].
Substituting the given values V=[tex]\frac{(0.2)(8.314)(300)}{100}[/tex]
V= 4.9884 Liters
We used the value of R to be 8.314 kPa*L/K*mol for the reason of unit consistency.
More more information about ideal gas law you can visit this link https://brainly.ph/question/2081255
22. which of the following is not a covalent compound? Aethane B.carbon tetrachloride C.carbon dioxide D. hydrogen iodide
Answer:
the correct answer po is letter B
hope it helps po paki brainliest naman po
23. Hydrogen Gas boiling point fixed temperature or temperature different in different times
Answer:
temperature different in different times
Explanation:
24. what is the boiling point of hydrogen gas
Answer:
the boiling point of hydrogen gas is
-252.9 °C
25. the boiling point of water is greater than the hydrogen sulfide because of
Answer:
Water has a higher boiling point than hydrogen sulphide. The intermolecular attractions between water molecules are stronger than H2S molecules due to hydrogen bonding in H2O due to high electronegativity and small size of oxygen atom.
Explanation:
#CARRYONLEARNING
paki brainleist po plsss
Answer:
Water has a higher boiling point than hydrogen sulphide. The intermolecular attractions between water molecules are stronger than H2S molecules due to hydrogen bonding in H2O due to high electronegativity and small size of oxygen atom.
26. (3 points) How many liters will 0.20 mol of hydrogen iodide at 300 K and 100.0 kPa occupy? Use R = 8.314 kPa*L/(K*mol) = 0.08205 atm*L/(mol*K).
For this question, we can simply use the ideal gas law wherein PV=nRT. We can first transform the original equation into our working equation then substitute the values in the corresponding variables. Since all the parameters are already given except for volume which is what we are looking for in this problem we then have,
V = (nRT)/P
where, n=0.20 moles
T=300K
P=100kPa
R=8.314 kPa*L/K*mol
V = (0.20mol)(8.314kPa*L/K*mol)(300K)/100kPa.
All units will cancel except for L
= 4.9884
= 5.0 L
Therefore, 0.20 mol of hydrogen iodide at 300 K and 100.0 kPa will occupy 5.0L.
27. what is the boiling point of hydrogen
Answer:
-252.9 degree celcius.
Explanation:
28. the boiling point of water is greater than hydrogen sulfide because of brainly
Answer:Because Water has a higher boiling point than hydrogen sulphide.
Explanation:
Hope it helps✨29. Iodoform decomposes to form diatomic iodine, hydrogen iodide, and Carbon. Write the balanced Chemical equation for the above-mentioned reaction.
Answer:
pag answer ug imo oi
Explanation:
ay sig tinapulan
30. Which has the lowest boiling point?A. Diamond chipB. Potassium iodideC. Salt solutionD. Plain water
Answer:
C.
Explanation:
I hope my answer may help
Answer:
B/A
Sana makatulong★★★
